Head vs breakz

[code] - 백준 1차열배열 10818,2582,2577,3053,1546,8958,4344 python 본문

Head/Code

[code] - 백준 1차열배열 10818,2582,2577,3053,1546,8958,4344 python

headbreakz 2020. 4. 3. 15:56

10818

#1차원 배열
#10818
a = int(input())
b = list(map(int, input().split()))

print(str(min(b))+" "+str(max(b)))

2582

#2562

a = []
for i in range(9):
    b = int(input())
    a.append(b)
    
print(max(a))
print(a.index(max(a))+1)
    

2577

#2577
a = int(input())
b = int(input())
c = int(input())
d = a*b*c
e = list(str(d))

for i in range(10):   
    print(e.count(str(i)))

3053

#3053
a = []
for i in range(10):
    b = int(input())
    c = b%42
    a.append(c)
    
print(len(set(a)))

1546

#1546
N = int(input())
score = list(map(int, input().split()))

print((sum(score, 0.0)/len(score))/max(score)*100)

8958

#8958
a = int(input())

for i in range(a):
    b = list(str(input()))   
    c = 0
    d = 0
    for j in range(len(b)):
        
        if b[0] == "O":
            c += 1
            d += c
            b.pop(0)
        else :
            b.pop(0)            
            c = 0
    print(d)

4344

#4344
a = int(input())
for i in range(a):
    b = list(map(int,input().split()))
    c = b.pop(0)
    d = sum(b)/len(b)
    e = 0
    for i in range(len(b)):
        if b[i] > d :
            e += 1    
    f = (e/len(b))*100
    print('%.3f' %f+"%")

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