목록permutation (1)
Head vs breakz

Permutations( 리스트 , 추출개수 ) from itertools import permutations num_5 = [1,2,3,4,5] answer_6 = list(permutations(num_5,2)) print(answer_6) [(1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 3), (2, 4), (2, 5), (3, 1), (3, 2), (3, 4), (3, 5), (4, 1), (4, 2), (4, 3), (4, 5), (5, 1), (5, 2), (5, 3), (5, 4)] num_6 = [1,2,3,4,5] answer_7 = list(permutations(num_5,3)) print(answer_7) [(1, 2, 3), (1, 2, 4), (1..
Head/Code
2020. 8. 26. 15:08