Head vs breakz

#호텔 방 배정 def solution(k, room_number): a = [0 for _ in range(k+1)] b = [] for i in range(len(room_number)): if a[room_number[i]] == 0 : a[room_number[i]] = room_number[i] b.append(room_number[i]) elif a[room_number[i]] != 0 : for j in range(1,len(room_number)-room_number[i]+1): if a[room_number[i]+j] == 0 : a[room_number[i]+j] = room_number[i]+j b.append(room_number[i]+j) answer = b return answe..

#크레인 인형뽑기 def solution(board, moves): box = [] cnt = 0 for i in range(len(moves)): for j in range(len(board)): if board[j][moves[i]-1] != 0 : box.append(board[j][moves[i]-1]) board[j][moves[i]-1] = 0 if len(box) > 1 and box[-1] == box [-2]: cnt += 2 box.pop(-1) box.pop(-1) break else : continue return cnt